Base | Representation |
---|---|
bin | 1110001001011111101000… |
… | …00110000100000011011111 |
3 | 11002011022220122021222122101 |
4 | 13010233310012010003133 |
5 | 13034221442044330403 |
6 | 150100523300225531 |
7 | 6360543554025160 |
oct | 704576406040337 |
9 | 132138818258571 |
10 | 31112543355103 |
11 | 9a05834692421 |
12 | 35a599b99b2a7 |
13 | 1448b91b03b22 |
14 | 797bd86b1767 |
15 | 38e496a7971d |
hex | 1c4bf41840df |
31112543355103 has 32 divisors (see below), whose sum is σ = 36060273930240. Its totient is φ = 26291939351040.
The previous prime is 31112543355073. The next prime is 31112543355161. The reversal of 31112543355103 is 30155334521113.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31112543355103 is a prime.
It is a super-2 number, since 2×311125433551032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31112543365103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1900690903 + ... + 1900707271.
It is an arithmetic number, because the mean of its divisors is an integer number (1126883560320).
Almost surely, 231112543355103 is an apocalyptic number.
31112543355103 is a deficient number, since it is larger than the sum of its proper divisors (4947730575137).
31112543355103 is a wasteful number, since it uses less digits than its factorization.
31112543355103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23047.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 31112543355103 its reverse (30155334521113), we get a palindrome (61267877876216).
The spelling of 31112543355103 in words is "thirty-one trillion, one hundred twelve billion, five hundred forty-three million, three hundred fifty-five thousand, one hundred three".
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