31113001131 has 4 divisors (see below), whose sum is σ = 41484001512. Its totient is φ = 20742000752.

The previous prime is 31113001123. The next prime is 31113001141. The reversal of 31113001131 is 13110031113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31113001131 - 2³ = 31113001123 is a prime.

It is a super-2 number, since 2×31113001131² (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 31113001131.

It is not an unprimeable number, because it can be changed into a prime (31113001111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5185500186 + ... + 5185500191.

It is an arithmetic number, because the mean of its divisors is an integer number (10371000378).

Almost surely, 2^31113001131 is an apocalyptic number.

31113001131 is a deficient number, since it is larger than the sum of its proper divisors (10371000381).

31113001131 is a wasteful number, since it uses less digits than its factorization.

31113001131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10371000380.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 31113001131 its reverse (13110031113), we get a palindrome (44223032244).

The spelling of 31113001131 in words is "thirty-one billion, one hundred thirteen million, one thousand, one hundred thirty-one".