Base | Representation |
---|---|
bin | 100011010111110001001101… |
… | …1100110010101101100000011 |
3 | 1111210121202000112111221012012 |
4 | 1012233202123212111230003 |
5 | 311240023311102103102 |
6 | 3021415100131123135 |
7 | 122351255316660164 |
oct | 10657423346255403 |
9 | 1453552015457165 |
10 | 311130041441027 |
11 | 90154567282846 |
12 | 2aa8b1054434ab |
13 | 1047b58b1800c3 |
14 | 56b8abab8376b |
15 | 25e8316815752 |
hex | 11af89b995b03 |
311130041441027 has 2 divisors, whose sum is σ = 311130041441028. Its totient is φ = 311130041441026.
The previous prime is 311130041441003. The next prime is 311130041441033. The reversal of 311130041441027 is 720144140031113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311130041441027 - 222 = 311130037246723 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311130041440984 and 311130041441002.
It is not a weakly prime, because it can be changed into another prime (311130041441827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155565020720513 + 155565020720514.
It is an arithmetic number, because the mean of its divisors is an integer number (155565020720514).
Almost surely, 2311130041441027 is an apocalyptic number.
311130041441027 is a deficient number, since it is larger than the sum of its proper divisors (1).
311130041441027 is an equidigital number, since it uses as much as digits as its factorization.
311130041441027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 32.
The spelling of 311130041441027 in words is "three hundred eleven trillion, one hundred thirty billion, forty-one million, four hundred forty-one thousand, twenty-seven".
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