Base | Representation |
---|---|
bin | 1110001001100000011111… |
… | …11010101011100001111001 |
3 | 11002011101010011121202200211 |
4 | 13010300033322223201321 |
5 | 13034223421043224423 |
6 | 150101041453031121 |
7 | 6360561252414046 |
oct | 704601772534171 |
9 | 132141104552624 |
10 | 31113010133113 |
11 | 9a05a54118677 |
12 | 35a5ab01854a1 |
13 | 1448c3772652c |
14 | 797c4069a1cd |
15 | 38e4c2a2e10d |
hex | 1c4c0feab879 |
31113010133113 has 2 divisors, whose sum is σ = 31113010133114. Its totient is φ = 31113010133112.
The previous prime is 31113010133099. The next prime is 31113010133171. The reversal of 31113010133113 is 31133101031113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31019864924304 + 93145208809 = 5569548^2 + 305197^2 .
It is a cyclic number.
It is not a de Polignac number, because 31113010133113 - 213 = 31113010124921 is a prime.
It is not a weakly prime, because it can be changed into another prime (31113010136113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556505066556 + 15556505066557.
It is an arithmetic number, because the mean of its divisors is an integer number (15556505066557).
Almost surely, 231113010133113 is an apocalyptic number.
It is an amenable number.
31113010133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31113010133113 is an equidigital number, since it uses as much as digits as its factorization.
31113010133113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 22.
Adding to 31113010133113 its reverse (31133101031113), we get a palindrome (62246111164226).
The spelling of 31113010133113 in words is "thirty-one trillion, one hundred thirteen billion, ten million, one hundred thirty-three thousand, one hundred thirteen".
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