Base | Representation |
---|---|
bin | 101101010001101000000… |
… | …011101110100110101001 |
3 | 102000102210222212022111112 |
4 | 231101220003232212221 |
5 | 401433421321130324 |
6 | 10341151254240105 |
7 | 440532652516136 |
oct | 55215003564651 |
9 | 12012728768445 |
10 | 3111302130089 |
11 | a9a54aa3945a |
12 | 422ba8956035 |
13 | 197518a2c48a |
14 | aa832dd358d |
15 | 55deacecc0e |
hex | 2d4680ee9a9 |
3111302130089 has 2 divisors, whose sum is σ = 3111302130090. Its totient is φ = 3111302130088.
The previous prime is 3111302130007. The next prime is 3111302130119. The reversal of 3111302130089 is 9800312031113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2559984000025 + 551318130064 = 1599995^2 + 742508^2 .
It is a cyclic number.
It is not a de Polignac number, because 3111302130089 - 212 = 3111302125993 is a prime.
It is not a weakly prime, because it can be changed into another prime (3111302130389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555651065044 + 1555651065045.
It is an arithmetic number, because the mean of its divisors is an integer number (1555651065045).
Almost surely, 23111302130089 is an apocalyptic number.
It is an amenable number.
3111302130089 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111302130089 is an equidigital number, since it uses as much as digits as its factorization.
3111302130089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 32.
The spelling of 3111302130089 in words is "three trillion, one hundred eleven billion, three hundred two million, one hundred thirty thousand, eighty-nine".
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