Base | Representation |
---|---|
bin | 1110001001100000101011… |
… | …11111101010010011101010 |
3 | 11002011101101021111022212210 |
4 | 13010300111333222103222 |
5 | 13034224123144231442 |
6 | 150101055534345550 |
7 | 6360563631216561 |
oct | 704602577522352 |
9 | 132141337438783 |
10 | 31113112102122 |
11 | 9a05aa6734486 |
12 | 35a5b1a35b2b6 |
13 | 1448c528a931b |
14 | 797c50040bd8 |
15 | 38e4cb97219c |
hex | 1c4c15fea4ea |
31113112102122 has 8 divisors (see below), whose sum is σ = 62226224204256. Its totient is φ = 10371037367372.
The previous prime is 31113112102109. The next prime is 31113112102183. The reversal of 31113112102122 is 22120121131113.
It is a sphenic number, since it is the product of 3 distinct primes.
31113112102122 is an admirable number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2592759341838 + ... + 2592759341849.
It is an arithmetic number, because the mean of its divisors is an integer number (7778278025532).
Almost surely, 231113112102122 is an apocalyptic number.
31113112102122 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31113112102122 is a wasteful number, since it uses less digits than its factorization.
31113112102122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5185518683692.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 31113112102122 its reverse (22120121131113), we get a palindrome (53233233233235).
The spelling of 31113112102122 in words is "thirty-one trillion, one hundred thirteen billion, one hundred twelve million, one hundred two thousand, one hundred twenty-two".
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