31113131012113 has 4 divisors (see below), whose sum is σ = 31122948980260. Its totient is φ = 31103313043968.

The previous prime is 31113131012057. The next prime is 31113131012123. The reversal of 31113131012113 is 31121013131113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15943913238289 + 15169217773824 = 3992983^2 + 3894768^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31113131012113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31113131012123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4908979320 + ... + 4908985657.

It is an arithmetic number, because the mean of its divisors is an integer number (7780737245065).

Almost surely, 2^{31113131012113} is an apocalyptic number.

It is an amenable number.

31113131012113 is a deficient number, since it is larger than the sum of its proper divisors (9817968147).

31113131012113 is an equidigital number, since it uses as much as digits as its factorization.

31113131012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9817968146.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 31113131012113 its reverse (31121013131113), we get a palindrome (62234144143226).

The spelling of 31113131012113 in words is "thirty-one trillion, one hundred thirteen billion, one hundred thirty-one million, twelve thousand, one hundred thirteen".