311132414113 has 4 divisors (see below), whose sum is σ = 311161055920. Its totient is φ = 311103772308.

The previous prime is 311132414111. The next prime is 311132414137. The reversal of 311132414113 is 311414231113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311414231113 = 59 ⋅5278207307.

It is a cyclic number.

It is not a de Polignac number, because 311132414113 - 2¹ = 311132414111 is a prime.

It is a super-2 number, since 2×311132414113² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311132414111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14304603 + ... + 14326336.

It is an arithmetic number, because the mean of its divisors is an integer number (77790263980).

Almost surely, 2^311132414113 is an apocalyptic number.

It is an amenable number.

311132414113 is a deficient number, since it is larger than the sum of its proper divisors (28641807).

311132414113 is a wasteful number, since it uses less digits than its factorization.

311132414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28641806.

The product of its digits is 864, while the sum is 25.

Adding to 311132414113 its reverse (311414231113), we get a palindrome (622546645226).

The spelling of 311132414113 in words is "three hundred eleven billion, one hundred thirty-two million, four hundred fourteen thousand, one hundred thirteen".