Base | Representation |
---|---|
bin | 100011010111110010100110… |
… | …1111010100111001101100100 |
3 | 1111210122000202000211221222021 |
4 | 1012233211031322213031210 |
5 | 311240100422433201012 |
6 | 3021420313040512524 |
7 | 122351422414443325 |
oct | 10657451572471544 |
9 | 1453560660757867 |
10 | 311133033100132 |
11 | 90155861a66591 |
12 | 2aa8b7bb31b744 |
13 | 1047b946c03ca9 |
14 | 56b8cc221844c |
15 | 25e843e2ad007 |
hex | 11af94dea7364 |
311133033100132 has 12 divisors (see below), whose sum is σ = 549571432299120. Its totient is φ = 154112623871816.
The previous prime is 311133033100121. The next prime is 311133033100171. The reversal of 311133033100132 is 231001330331113.
It is a junction number, because it is equal to n+sod(n) for n = 311133033100097 and 311133033100106.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363473169082 + ... + 363473169937.
It is an arithmetic number, because the mean of its divisors is an integer number (45797619358260).
Almost surely, 2311133033100132 is an apocalyptic number.
It is an amenable number.
311133033100132 is a deficient number, since it is larger than the sum of its proper divisors (238438399198988).
311133033100132 is a wasteful number, since it uses less digits than its factorization.
311133033100132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 726946339130 (or 726946339128 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 311133033100132 its reverse (231001330331113), we get a palindrome (542134363431245).
The spelling of 311133033100132 in words is "three hundred eleven trillion, one hundred thirty-three billion, thirty-three million, one hundred thousand, one hundred thirty-two".
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