Base | Representation |
---|---|
bin | 1110001001100001000011… |
… | …10111101010001011101001 |
3 | 11002011101220011101012120221 |
4 | 13010300201313222023221 |
5 | 13034230030200043144 |
6 | 150101131412450041 |
7 | 6360601600513123 |
oct | 704604167521351 |
9 | 132141804335527 |
10 | 31113311331049 |
11 | 9a06099140092 |
12 | 35a5b75019921 |
13 | 1448c84c5366c |
14 | 797c6c6a2213 |
15 | 38e4de1c7d84 |
hex | 1c4c21dea2e9 |
31113311331049 has 2 divisors, whose sum is σ = 31113311331050. Its totient is φ = 31113311331048.
The previous prime is 31113311330987. The next prime is 31113311331059. The reversal of 31113311331049 is 94013311331113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27965905358400 + 3147405972649 = 5288280^2 + 1774093^2 .
It is a cyclic number.
It is not a de Polignac number, because 31113311331049 - 227 = 31113177113321 is a prime.
It is not a weakly prime, because it can be changed into another prime (31113311331059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556655665524 + 15556655665525.
It is an arithmetic number, because the mean of its divisors is an integer number (15556655665525).
Almost surely, 231113311331049 is an apocalyptic number.
It is an amenable number.
31113311331049 is a deficient number, since it is larger than the sum of its proper divisors (1).
31113311331049 is an equidigital number, since it uses as much as digits as its factorization.
31113311331049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 34.
The spelling of 31113311331049 in words is "thirty-one trillion, one hundred thirteen billion, three hundred eleven million, three hundred thirty-one thousand, forty-nine".
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