3111341001 has 4 divisors (see below), whose sum is σ = 4148454672. Its totient is φ = 2074227332.

The previous prime is 3111340993. The next prime is 3111341021. The reversal of 3111341001 is 1001431113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1001431113 = 3 ⋅333810371.

It is a cyclic number.

It is not a de Polignac number, because 3111341001 - 2³ = 3111340993 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3111341021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518556831 + ... + 518556836.

It is an arithmetic number, because the mean of its divisors is an integer number (1037113668).

Almost surely, 2^3111341001 is an apocalyptic number.

It is an amenable number.

3111341001 is a deficient number, since it is larger than the sum of its proper divisors (1037113671).

3111341001 is a wasteful number, since it uses less digits than its factorization.

3111341001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1037113670.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 3111341001 is about 55779.3958464951. The cubic root of 3111341001 is about 1459.8756698092.

Adding to 3111341001 its reverse (1001431113), we get a palindrome (4112772114).

The spelling of 3111341001 in words is "three billion, one hundred eleven million, three hundred forty-one thousand, one".