3111411211121 has 2 divisors, whose sum is σ = 3111411211122. Its totient is φ = 3111411211120.

The previous prime is 3111411211099. The next prime is 3111411211169. The reversal of 3111411211121 is 1211121141113.

It is a m-pointer prime, because the next prime (3111411211169) can be obtained adding 3111411211121 to its product of digits (48).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2906803354225 + 204607856896 = 1704935^2 + 452336^2 .

It is a cyclic number.

It is not a de Polignac number, because 3111411211121 - 2⁶ = 3111411211057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3111411211093 and 3111411211102.

It is not a weakly prime, because it can be changed into another prime (3111411211621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555705605560 + 1555705605561.

It is an arithmetic number, because the mean of its divisors is an integer number (1555705605561).

Almost surely, 2^{3111411211121} is an apocalyptic number.

It is an amenable number.

3111411211121 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111411211121 is an equidigital number, since it uses as much as digits as its factorization.

3111411211121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 20.

Adding to 3111411211121 its reverse (1211121141113), we get a palindrome (4322532352234).

The spelling of 3111411211121 in words is "three trillion, one hundred eleven billion, four hundred eleven million, two hundred eleven thousand, one hundred twenty-one".