31115130001 has 4 divisors (see below), whose sum is σ = 32118843904. Its totient is φ = 30111416100.

The previous prime is 31115129989. The next prime is 31115130017. The reversal of 31115130001 is 10003151113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31115130001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31115130061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501856905 + ... + 501856966.

It is an arithmetic number, because the mean of its divisors is an integer number (8029710976).

Almost surely, 2^31115130001 is an apocalyptic number.

31115130001 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

It is an amenable number.

31115130001 is a deficient number, since it is larger than the sum of its proper divisors (1003713903).

31115130001 is a wasteful number, since it uses less digits than its factorization.

31115130001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1003713902.

The product of its (nonzero) digits is 45, while the sum is 16.

Adding to 31115130001 its reverse (10003151113), we get a palindrome (41118281114).

The spelling of 31115130001 in words is "thirty-one billion, one hundred fifteen million, one hundred thirty thousand, one".