Base | Representation |
---|---|
bin | 101101010010010001110… |
… | …001100001110011000010 |
3 | 102000111121202210111102122 |
4 | 231102101301201303002 |
5 | 401441340003031424 |
6 | 10341344535044242 |
7 | 440556211365305 |
oct | 55222161416302 |
9 | 12014552714378 |
10 | 3112002002114 |
11 | a9a87a000695 |
12 | 423163210682 |
13 | 1975caa25535 |
14 | aa89bd36b3c |
15 | 55e3c49745e |
hex | 2d491c61cc2 |
3112002002114 has 32 divisors (see below), whose sum is σ = 4911781550400. Its totient is φ = 1476591793600.
The previous prime is 3112002002093. The next prime is 3112002002237. The reversal of 3112002002114 is 4112002002113.
It is a super-2 number, since 2×31120020021142 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3112002002092 and 3112002002101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17834189 + ... + 18007839.
It is an arithmetic number, because the mean of its divisors is an integer number (153493173450).
Almost surely, 23112002002114 is an apocalyptic number.
3112002002114 is a deficient number, since it is larger than the sum of its proper divisors (1799779548286).
3112002002114 is a wasteful number, since it uses less digits than its factorization.
3112002002114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 178978.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 3112002002114 its reverse (4112002002113), we get a palindrome (7224004004227).
Subtracting 3112002002114 from its reverse (4112002002113), we obtain a palindrome (999999999999).
The spelling of 3112002002114 in words is "three trillion, one hundred twelve billion, two million, two thousand, one hundred fourteen".
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