Base | Representation |
---|---|
bin | 1110001001101110000110… |
… | …01101010101100110101011 |
3 | 11002012001222010110120202111 |
4 | 13010313003031111212223 |
5 | 13034333400124104003 |
6 | 150104250253143151 |
7 | 6361240240623442 |
oct | 704670315254653 |
9 | 132161863416674 |
10 | 31120313113003 |
11 | 9a090614a1544 |
12 | 35a73a9a8aab7 |
13 | 144982c7316ca |
14 | 798334563d59 |
15 | 38e79dc44e6d |
hex | 1c4dc33559ab |
31120313113003 has 4 divisors (see below), whose sum is σ = 31130621268760. Its totient is φ = 31110004957248.
The previous prime is 31120313112983. The next prime is 31120313113009. The reversal of 31120313113003 is 30031131302113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31120313113003 - 25 = 31120313112971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31120313113009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5154073350 + ... + 5154079387.
It is an arithmetic number, because the mean of its divisors is an integer number (7782655317190).
Almost surely, 231120313113003 is an apocalyptic number.
31120313113003 is a deficient number, since it is larger than the sum of its proper divisors (10308155757).
31120313113003 is a wasteful number, since it uses less digits than its factorization.
31120313113003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10308155756.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 31120313113003 its reverse (30031131302113), we get a palindrome (61151444415116).
The spelling of 31120313113003 in words is "thirty-one trillion, one hundred twenty billion, three hundred thirteen million, one hundred thirteen thousand, three".
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