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31121021122003 = 97320835269299
BaseRepresentation
bin1110001001101111011010…
…11010001011010111010011
311002012010210110201011112001
413010313231122023113103
513034341322401401003
6150104444424214431
76361263625612561
oct704675532132723
9132163713634461
1031121021122003
119a0939511114a
1235a756700a417
131449913316347
147983a05c4a31
1538e7e0e9a61d
hex1c4ded68b5d3

31121021122003 has 4 divisors (see below), whose sum is σ = 31441856391400. Its totient is φ = 30800185852608.

The previous prime is 31121021121973. The next prime is 31121021122021. The reversal of 31121021122003 is 30022112012113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31121021122003 - 213 = 31121021113811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31121021122903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160417634553 + ... + 160417634746.

It is an arithmetic number, because the mean of its divisors is an integer number (7860464097850).

Almost surely, 231121021122003 is an apocalyptic number.

31121021122003 is a deficient number, since it is larger than the sum of its proper divisors (320835269397).

31121021122003 is an equidigital number, since it uses as much as digits as its factorization.

31121021122003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 320835269396.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 31121021122003 its reverse (30022112012113), we get a palindrome (61143133134116).

The spelling of 31121021122003 in words is "thirty-one trillion, one hundred twenty-one billion, twenty-one million, one hundred twenty-two thousand, three".

Divisors: 1 97 320835269299 31121021122003