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311211314243 = 3120389492377
BaseRepresentation
bin1001000011101011010…
…00111100110001000011
31002202021211222210121222
410201311220330301003
520044330044023433
6354545110305255
731325051344604
oct4416550746103
91082254883558
10311211314243
1110aa90745665
125039405822b
132346877236b
14110c40dbdab
158166a8eb98
hex4875a3cc43

311211314243 has 8 divisors (see below), whose sum is σ = 321266797440. Its totient is φ = 301156856640.

The previous prime is 311211314213. The next prime is 311211314257. The reversal of 311211314243 is 342413112113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 311211314243 - 230 = 310137572419 is a prime.

It is a super-2 number, since 2×3112113142432 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311211314213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 385871 + ... + 878247.

It is an arithmetic number, because the mean of its divisors is an integer number (40158349680).

Almost surely, 2311211314243 is an apocalyptic number.

311211314243 is a deficient number, since it is larger than the sum of its proper divisors (10055483197).

311211314243 is a wasteful number, since it uses less digits than its factorization.

311211314243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 512797.

The product of its digits is 1728, while the sum is 26.

Adding to 311211314243 its reverse (342413112113), we get a palindrome (653624426356).

The spelling of 311211314243 in words is "three hundred eleven billion, two hundred eleven million, three hundred fourteen thousand, two hundred forty-three".

Divisors: 1 31 20389 492377 632059 15263687 10039074653 311211314243