Base | Representation |
---|---|
bin | 101101010010011001100… |
… | …010100111110000110001 |
3 | 102000111221211222221010220 |
4 | 231102121202213300301 |
5 | 401442121332441423 |
6 | 10341405512043253 |
7 | 440562353116656 |
oct | 55223142476061 |
9 | 12014854887126 |
10 | 3112132312113 |
11 | a9a936614500 |
12 | 42319a993529 |
13 | 19761ba1c146 |
14 | aa8b1377c2d |
15 | 55e48b379e3 |
hex | 2d4998a7c31 |
3112132312113 has 96 divisors (see below), whose sum is σ = 4667326465536. Its totient is φ = 1842736896000.
The previous prime is 3112132312103. The next prime is 3112132312127.
3112132312113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3112132312113 - 24 = 3112132312097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3112132312103) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3307260223 + ... + 3307261163.
It is an arithmetic number, because the mean of its divisors is an integer number (48617984016).
Almost surely, 23112132312113 is an apocalyptic number.
3112132312113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
3112132312113 is a deficient number, since it is larger than the sum of its proper divisors (1555194153423).
3112132312113 is a wasteful number, since it uses less digits than its factorization.
3112132312113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2087 (or 2076 counting only the distinct ones).
The product of its digits is 648, while the sum is 24.
The spelling of 3112132312113 in words is "three trillion, one hundred twelve billion, one hundred thirty-two million, three hundred twelve thousand, one hundred thirteen".
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