3112200144331 has 2 divisors, whose sum is σ = 3112200144332. Its totient is φ = 3112200144330.

The previous prime is 3112200144311. The next prime is 3112200144337. The reversal of 3112200144331 is 1334410022113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3112200144331 - 2¹³ = 3112200136139 is a prime.

It is a super-2 number, since 2×3112200144331² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3112200144296 and 3112200144305.

It is not a weakly prime, because it can be changed into another prime (3112200144337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556100072165 + 1556100072166.

It is an arithmetic number, because the mean of its divisors is an integer number (1556100072166).

Almost surely, 2^{3112200144331} is an apocalyptic number.

3112200144331 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112200144331 is an equidigital number, since it uses as much as digits as its factorization.

3112200144331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 3112200144331 its reverse (1334410022113), we get a palindrome (4446610166444).

The spelling of 3112200144331 in words is "three trillion, one hundred twelve billion, two hundred million, one hundred forty-four thousand, three hundred thirty-one".