311221114993 has 2 divisors, whose sum is σ = 311221114994. Its totient is φ = 311221114992.

The previous prime is 311221114979. The next prime is 311221115033. The reversal of 311221114993 is 399411122113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 265908329569 + 45312785424 = 515663^2 + 212868^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311221114993 is a prime.

It is a super-3 number, since 3×311221114993³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (311221114943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155610557496 + 155610557497.

It is an arithmetic number, because the mean of its divisors is an integer number (155610557497).

Almost surely, 2^311221114993 is an apocalyptic number.

It is an amenable number.

311221114993 is a deficient number, since it is larger than the sum of its proper divisors (1).

311221114993 is an equidigital number, since it uses as much as digits as its factorization.

311221114993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11664, while the sum is 37.

The spelling of 311221114993 in words is "three hundred eleven billion, two hundred twenty-one million, one hundred fourteen thousand, nine hundred ninety-three".