Base | Representation |
---|---|
bin | 1110001001110001011111… |
… | …01100000111110001000010 |
3 | 11002012020122222010121220100 |
4 | 13010320233230013301002 |
5 | 13034401112034401424 |
6 | 150105151030223230 |
7 | 6361333320505446 |
oct | 704705754076102 |
9 | 132166588117810 |
10 | 31122133122114 |
11 | 9a09905882301 |
12 | 35a78174b4b16 |
13 | 1449a5c809088 |
14 | 798468168826 |
15 | 38e858901dc9 |
hex | 1c4e2fb07c42 |
31122133122114 has 12 divisors (see below), whose sum is σ = 67431288431286. Its totient is φ = 10374044374032.
The previous prime is 31122133122079. The next prime is 31122133122127. The reversal of 31122133122114 is 41122133122113.
31122133122114 is a `hidden beast` number, since 3 + 1 + 122 + 13 + 312 + 211 + 4 = 666.
It can be written as a sum of positive squares in only one way, i.e., 18377468741025 + 12744664381089 = 4286895^2 + 3569967^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 864503697819 + ... + 864503697854.
Almost surely, 231122133122114 is an apocalyptic number.
31122133122114 is an abundant number, since it is smaller than the sum of its proper divisors (36309155309172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31122133122114 is a wasteful number, since it uses less digits than its factorization.
31122133122114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1729007395681 (or 1729007395678 counting only the distinct ones).
The product of its digits is 1728, while the sum is 27.
Adding to 31122133122114 its reverse (41122133122113), we get a palindrome (72244266244227).
Subtracting 31122133122114 from its reverse (41122133122113), we obtain a palindrome (9999999999999).
The spelling of 31122133122114 in words is "thirty-one trillion, one hundred twenty-two billion, one hundred thirty-three million, one hundred twenty-two thousand, one hundred fourteen".
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