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3112213421401 = 7444601917343
BaseRepresentation
bin101101010010011110011…
…000000001110101011001
3102000112011111121201011121
4231102132120001311121
5401442303113441101
610341421530325241
7440564356413130
oct55223630016531
912015144551147
103112213421401
11a9a978383077
12423201b89821
1319763277a3c6
14aa8bc04c917
1555e50d0a0a1
hex2d49e601d59

3112213421401 has 4 divisors (see below), whose sum is σ = 3556815338752. Its totient is φ = 2667611504052.

The previous prime is 3112213421389. The next prime is 3112213421407. The reversal of 3112213421401 is 1041243122113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3112213421401 - 233 = 3103623486809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3112213421407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222300958665 + ... + 222300958678.

It is an arithmetic number, because the mean of its divisors is an integer number (889203834688).

Almost surely, 23112213421401 is an apocalyptic number.

It is an amenable number.

3112213421401 is a deficient number, since it is larger than the sum of its proper divisors (444601917351).

3112213421401 is an equidigital number, since it uses as much as digits as its factorization.

3112213421401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444601917350.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 3112213421401 its reverse (1041243122113), we get a palindrome (4153456543514).

The spelling of 3112213421401 in words is "three trillion, one hundred twelve billion, two hundred thirteen million, four hundred twenty-one thousand, four hundred one".

Divisors: 1 7 444601917343 3112213421401