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3112222114 = 21556111057
BaseRepresentation
bin1011100110000000…
…1011110110100010
322000220012021010201
42321200023312202
522333212101424
61232453415414
7140060310601
oct27140136642
98026167121
103112222114
11135784a5a1
1272a33a56a
133a7a17161
14217499a38
1513335ed44
hexb980bda2

3112222114 has 4 divisors (see below), whose sum is σ = 4668333174. Its totient is φ = 1556111056.

The previous prime is 3112222111. The next prime is 3112222117. The reversal of 3112222114 is 4112222113.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (3112222111) and next prime (3112222117).

It can be written as a sum of positive squares in only one way, i.e., 2844408889 + 267813225 = 53333^2 + 16365^2 .

It is a junction number, because it is equal to n+sod(n) for n = 3112222091 and 3112222100.

It is not an unprimeable number, because it can be changed into a prime (3112222111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 778055527 + ... + 778055530.

Almost surely, 23112222114 is an apocalyptic number.

3112222114 is a deficient number, since it is larger than the sum of its proper divisors (1556111060).

3112222114 is a wasteful number, since it uses less digits than its factorization.

3112222114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1556111059.

The product of its digits is 192, while the sum is 19.

The square root of 3112222114 is about 55787.2934815806. The cubic root of 3112222114 is about 1460.0134661296.

Adding to 3112222114 its reverse (4112222113), we get a palindrome (7224444227).

Subtracting 3112222114 from its reverse (4112222113), we obtain a palindrome (999999999).

The spelling of 3112222114 in words is "three billion, one hundred twelve million, two hundred twenty-two thousand, one hundred fourteen".

Divisors: 1 2 1556111057 3112222114