Base | Representation |
---|---|
bin | 100011011000100000001110… |
… | …1010101001100010011001011 |
3 | 1111210222101121200001111220011 |
4 | 1012301000131111030103023 |
5 | 311243202043032411021 |
6 | 3021533314255212351 |
7 | 122361461241354451 |
oct | 10661003525142313 |
9 | 1453871550044804 |
10 | 311231002232011 |
11 | 90193365a91384 |
12 | 2aaa67a0b170b7 |
13 | 10487c5aa4c204 |
14 | 56bd9376669d1 |
15 | 25eac75088de1 |
hex | 11b101d54c4cb |
311231002232011 has 2 divisors, whose sum is σ = 311231002232012. Its totient is φ = 311231002232010.
The previous prime is 311231002231949. The next prime is 311231002232021. The reversal of 311231002232011 is 110232200132113.
It is a strong prime.
It is an emirp because it is prime and its reverse (110232200132113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311231002232011 - 211 = 311231002229963 is a prime.
It is not a weakly prime, because it can be changed into another prime (311231002232021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155615501116005 + 155615501116006.
It is an arithmetic number, because the mean of its divisors is an integer number (155615501116006).
Almost surely, 2311231002232011 is an apocalyptic number.
311231002232011 is a deficient number, since it is larger than the sum of its proper divisors (1).
311231002232011 is an equidigital number, since it uses as much as digits as its factorization.
311231002232011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 311231002232011 its reverse (110232200132113), we get a palindrome (421463202364124).
The spelling of 311231002232011 in words is "three hundred eleven trillion, two hundred thirty-one billion, two million, two hundred thirty-two thousand, eleven".
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