Base | Representation |
---|---|
bin | 1001000011101110001… |
… | …00111100101011010011 |
3 | 1002202100112101001202202 |
4 | 10201313010330223103 |
5 | 20044402232243443 |
6 | 354551331233415 |
7 | 31325463341321 |
oct | 4416704745323 |
9 | 1082315331682 |
10 | 311235431123 |
11 | 10aaa3317a71 |
12 | 503a014886b |
13 | 234707675c6 |
14 | 110c73b8d11 |
15 | 8168c557b8 |
hex | 487713cad3 |
311235431123 has 2 divisors, whose sum is σ = 311235431124. Its totient is φ = 311235431122.
The previous prime is 311235431071. The next prime is 311235431131. The reversal of 311235431123 is 321134532113.
It is a strong prime.
It is an emirp because it is prime and its reverse (321134532113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311235431123 - 28 = 311235430867 is a prime.
It is a super-2 number, since 2×3112354311232 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311235431183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155617715561 + 155617715562.
It is an arithmetic number, because the mean of its divisors is an integer number (155617715562).
Almost surely, 2311235431123 is an apocalyptic number.
311235431123 is a deficient number, since it is larger than the sum of its proper divisors (1).
311235431123 is an equidigital number, since it uses as much as digits as its factorization.
311235431123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 29.
Adding to 311235431123 its reverse (321134532113), we get a palindrome (632369963236).
The spelling of 311235431123 in words is "three hundred eleven billion, two hundred thirty-five million, four hundred thirty-one thousand, one hundred twenty-three".
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