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311264423223097 is a prime number
BaseRepresentation
bin100011011000101111110010…
…1011000001001111100111001
31111211002120212211112202210211
41012301133211120021330321
5311244224014321114342
63022000522455111121
7122364053401165321
oct10661374530117471
91454076784482724
10311264423223097
11901a6556298673
122aab11696724a1
131048b155aa9696
1456c13c8184281
1525eba7e1b4c17
hex11b17e5609f39

311264423223097 has 2 divisors, whose sum is σ = 311264423223098. Its totient is φ = 311264423223096.

The previous prime is 311264423223059. The next prime is 311264423223137. The reversal of 311264423223097 is 790322324462113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 232388194672656 + 78876228550441 = 15244284^2 + 8881229^2 .

It is a cyclic number.

It is not a de Polignac number, because 311264423223097 - 231 = 311262275739449 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 311264423223097.

It is not a weakly prime, because it can be changed into another prime (311264423221097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155632211611548 + 155632211611549.

It is an arithmetic number, because the mean of its divisors is an integer number (155632211611549).

Almost surely, 2311264423223097 is an apocalyptic number.

It is an amenable number.

311264423223097 is a deficient number, since it is larger than the sum of its proper divisors (1).

311264423223097 is an equidigital number, since it uses as much as digits as its factorization.

311264423223097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2612736, while the sum is 49.

The spelling of 311264423223097 in words is "three hundred eleven trillion, two hundred sixty-four billion, four hundred twenty-three million, two hundred twenty-three thousand, ninety-seven".