Base | Representation |
---|---|
bin | 100011011001000000100010… |
… | …1111101010000101111001001 |
3 | 1111211020000202100102010022121 |
4 | 1012302001011331100233021 |
5 | 311300321211221120241 |
6 | 3022025233033051241 |
7 | 122366466123620500 |
oct | 10662010575205711 |
9 | 1454200670363277 |
10 | 311300403301321 |
11 | 9020a83a095a05 |
12 | 2aab812b256b21 |
13 | 1049166b0838b5 |
14 | 56c303c8d3837 |
15 | 25ec987cddad1 |
hex | 11b2045f50bc9 |
311300403301321 has 24 divisors (see below), whose sum is σ = 373808149693440. Its totient is φ = 258220330401600.
The previous prime is 311300403301157. The next prime is 311300403301337. The reversal of 311300403301321 is 123103304003113.
It is a de Polignac number, because none of the positive numbers 2k-311300403301321 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311300403301421) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 495607741 + ... + 496235461.
It is an arithmetic number, because the mean of its divisors is an integer number (15575339570560).
Almost surely, 2311300403301321 is an apocalyptic number.
311300403301321 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
It is an amenable number.
311300403301321 is a deficient number, since it is larger than the sum of its proper divisors (62507746392119).
311300403301321 is a wasteful number, since it uses less digits than its factorization.
311300403301321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 954245 (or 954238 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 311300403301321 its reverse (123103304003113), we get a palindrome (434403707304434).
The spelling of 311300403301321 in words is "three hundred eleven trillion, three hundred billion, four hundred three million, three hundred one thousand, three hundred twenty-one".
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