Base | Representation |
---|---|
bin | 100011011001000000111110… |
… | …0110010000001101110001001 |
3 | 1111211020010010110011220011122 |
4 | 1012302001330302001232021 |
5 | 311300330102203244423 |
6 | 3022025504211405025 |
7 | 122366530663041410 |
oct | 10662017462015611 |
9 | 1454203113156148 |
10 | 311301323103113 |
11 | 90210171312682 |
12 | 2aab83472b3775 |
13 | 104917867c1405 |
14 | 56c30c8b26477 |
15 | 25ec9dd92c8c8 |
hex | 11b207cc81b89 |
311301323103113 has 4 divisors (see below), whose sum is σ = 355772940689280. Its totient is φ = 266829705516948.
The previous prime is 311301323103107. The next prime is 311301323103151.
311301323103113 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 311301323103113 - 222 = 311301318908809 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (311301323103013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22235808793073 + ... + 22235808793086.
It is an arithmetic number, because the mean of its divisors is an integer number (88943235172320).
Almost surely, 2311301323103113 is an apocalyptic number.
It is an amenable number.
311301323103113 is a deficient number, since it is larger than the sum of its proper divisors (44471617586167).
311301323103113 is an equidigital number, since it uses as much as digits as its factorization.
311301323103113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44471617586166.
The product of its (nonzero) digits is 1458, while the sum is 26.
The spelling of 311301323103113 in words is "three hundred eleven trillion, three hundred one billion, three hundred twenty-three million, one hundred three thousand, one hundred thirteen".
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