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311301424321 is a prime number
BaseRepresentation
bin1001000011110110000…
…00101100010011000001
31002202112010112212102021
410201323000230103001
520100021131034241
6355002045521441
731330224306316
oct4417300542301
91082463485367
10311301424321
111100275a16a8
12503ba273281
1323481332434
14110d2076d0d
15816e93e0d1
hex487b02c4c1

311301424321 has 2 divisors, whose sum is σ = 311301424322. Its totient is φ = 311301424320.

The previous prime is 311301424283. The next prime is 311301424331. The reversal of 311301424321 is 123424103113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 207334515600 + 103966908721 = 455340^2 + 322439^2 .

It is a cyclic number.

It is not a de Polignac number, because 311301424321 - 29 = 311301423809 is a prime.

It is a super-3 number, since 3×3113014243213 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (311301424331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155650712160 + 155650712161.

It is an arithmetic number, because the mean of its divisors is an integer number (155650712161).

Almost surely, 2311301424321 is an apocalyptic number.

It is an amenable number.

311301424321 is a deficient number, since it is larger than the sum of its proper divisors (1).

311301424321 is an equidigital number, since it uses as much as digits as its factorization.

311301424321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 311301424321 its reverse (123424103113), we get a palindrome (434725527434).

The spelling of 311301424321 in words is "three hundred eleven billion, three hundred one million, four hundred twenty-four thousand, three hundred twenty-one".