Base | Representation |
---|---|
bin | 101101010011010011011… |
… | …001111101101001101011 |
3 | 102000121110111202010120201 |
4 | 231103103121331221223 |
5 | 402001113344333003 |
6 | 10342050111533031 |
7 | 440625411631411 |
oct | 55232331755153 |
9 | 12017414663521 |
10 | 3113103121003 |
11 | aa029460a5a7 |
12 | 42340bb2a177 |
13 | 197744ba8585 |
14 | aa9642872b1 |
15 | 55ea3e9eb1d |
hex | 2d4d367da6b |
3113103121003 has 4 divisors (see below), whose sum is σ = 3113218967040. Its totient is φ = 3112987274968.
The previous prime is 3113103120997. The next prime is 3113103121019. The reversal of 3113103121003 is 3001213013113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3113103121003 - 25 = 3113103120971 is a prime.
It is a super-2 number, since 2×31131031210032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3113103127003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57882700 + ... + 57936457.
It is an arithmetic number, because the mean of its divisors is an integer number (778304741760).
Almost surely, 23113103121003 is an apocalyptic number.
3113103121003 is a deficient number, since it is larger than the sum of its proper divisors (115846037).
3113103121003 is a wasteful number, since it uses less digits than its factorization.
3113103121003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 115846036.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 3113103121003 its reverse (3001213013113), we get a palindrome (6114316134116).
The spelling of 3113103121003 in words is "three trillion, one hundred thirteen billion, one hundred three million, one hundred twenty-one thousand, three".
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