Base | Representation |
---|---|
bin | 1001000011110111000… |
… | …10101000110111011001 |
3 | 1002202112202021222022221 |
4 | 10201323202220313121 |
5 | 20100030420320121 |
6 | 355003004344041 |
7 | 31330363041415 |
oct | 4417342506731 |
9 | 1082482258287 |
10 | 311310323161 |
11 | 11003161a512 |
12 | 50401245021 |
13 | 23483129a16 |
14 | 110d3311d45 |
15 | 81705eab41 |
hex | 487b8a8dd9 |
311310323161 has 2 divisors, whose sum is σ = 311310323162. Its totient is φ = 311310323160.
The previous prime is 311310323153. The next prime is 311310323183. The reversal of 311310323161 is 161323013113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 240277412761 + 71032910400 = 490181^2 + 266520^2 .
It is an emirp because it is prime and its reverse (161323013113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311310323161 - 23 = 311310323153 is a prime.
It is not a weakly prime, because it can be changed into another prime (311310323461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155655161580 + 155655161581.
It is an arithmetic number, because the mean of its divisors is an integer number (155655161581).
Almost surely, 2311310323161 is an apocalyptic number.
It is an amenable number.
311310323161 is a deficient number, since it is larger than the sum of its proper divisors (1).
311310323161 is an equidigital number, since it uses as much as digits as its factorization.
311310323161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 311310323161 its reverse (161323013113), we get a palindrome (472633336274).
The spelling of 311310323161 in words is "three hundred eleven billion, three hundred ten million, three hundred twenty-three thousand, one hundred sixty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.101 sec. • engine limits •