Base | Representation |
---|---|
bin | 1110001010000010001100… |
… | …10010111100100010111001 |
3 | 11002020002211001021202100022 |
4 | 13011001012102330202321 |
5 | 13040022444144124423 |
6 | 150113233031420225 |
7 | 6362101510523606 |
oct | 705010622744271 |
9 | 132202731252308 |
10 | 31131102333113 |
11 | 9a12698754282 |
12 | 35a94bb224675 |
13 | 144a85ba99213 |
14 | 798a794476ad |
15 | 38ebd104adc8 |
hex | 1c50464bc8b9 |
31131102333113 has 2 divisors, whose sum is σ = 31131102333114. Its totient is φ = 31131102333112.
The previous prime is 31131102333103. The next prime is 31131102333157. The reversal of 31131102333113 is 31133320113113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30237769236544 + 893333096569 = 5498888^2 + 945163^2 .
It is a cyclic number.
It is not a de Polignac number, because 31131102333113 - 210 = 31131102332089 is a prime.
It is not a weakly prime, because it can be changed into another prime (31131102333103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565551166556 + 15565551166557.
It is an arithmetic number, because the mean of its divisors is an integer number (15565551166557).
Almost surely, 231131102333113 is an apocalyptic number.
It is an amenable number.
31131102333113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31131102333113 is an equidigital number, since it uses as much as digits as its factorization.
31131102333113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 31131102333113 its reverse (31133320113113), we get a palindrome (62264422446226).
The spelling of 31131102333113 in words is "thirty-one trillion, one hundred thirty-one billion, one hundred two million, three hundred thirty-three thousand, one hundred thirteen".
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