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3113122223113 = 7444731746159
BaseRepresentation
bin101101010011010100100…
…010110101010000001001
3102000121111211200121202021
4231103110202311100021
5402001133242114423
610342052033204441
7440626033200610
oct55232442652011
912017454617667
103113122223113
11aa02a4377271
12423416400721
13197748b360b6
14aa966a1a877
1555ea59c495d
hex2d4d48b5409

3113122223113 has 4 divisors (see below), whose sum is σ = 3557853969280. Its totient is φ = 2668390476948.

The previous prime is 3113122223093. The next prime is 3113122223177. The reversal of 3113122223113 is 3113222213113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 3113122223113 - 221 = 3113120125961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3113122223413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222365873073 + ... + 222365873086.

It is an arithmetic number, because the mean of its divisors is an integer number (889463492320).

Almost surely, 23113122223113 is an apocalyptic number.

It is an amenable number.

3113122223113 is a deficient number, since it is larger than the sum of its proper divisors (444731746167).

3113122223113 is an equidigital number, since it uses as much as digits as its factorization.

3113122223113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444731746166.

The product of its digits is 1296, while the sum is 25.

Adding to 3113122223113 its reverse (3113222213113), we get a palindrome (6226344436226).

The spelling of 3113122223113 in words is "three trillion, one hundred thirteen billion, one hundred twenty-two million, two hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 7 444731746159 3113122223113