Base | Representation |
---|---|
bin | 101101010011010101000… |
… | …001011000101000000001 |
3 | 102000121112101202112022121 |
4 | 231103111001120220001 |
5 | 402001142314413241 |
6 | 10342052521004241 |
7 | 440626161236224 |
oct | 55232501305001 |
9 | 12017471675277 |
10 | 3113130232321 |
11 | aa02a894774a |
12 | 423419023681 |
13 | 19774a6ab785 |
14 | aa967b035bb |
15 | 55ea6557ad1 |
hex | 2d4d5058a01 |
3113130232321 has 2 divisors, whose sum is σ = 3113130232322. Its totient is φ = 3113130232320.
The previous prime is 3113130232313. The next prime is 3113130232339. The reversal of 3113130232321 is 1232320313113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2290909280625 + 822220951696 = 1513575^2 + 906764^2 .
It is a cyclic number.
It is not a de Polignac number, because 3113130232321 - 23 = 3113130232313 is a prime.
It is not a weakly prime, because it can be changed into another prime (3113130232361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556565116160 + 1556565116161.
It is an arithmetic number, because the mean of its divisors is an integer number (1556565116161).
Almost surely, 23113130232321 is an apocalyptic number.
It is an amenable number.
3113130232321 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113130232321 is an equidigital number, since it uses as much as digits as its factorization.
3113130232321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3113130232321 its reverse (1232320313113), we get a palindrome (4345450545434).
The spelling of 3113130232321 in words is "three trillion, one hundred thirteen billion, one hundred thirty million, two hundred thirty-two thousand, three hundred twenty-one".
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