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311320152521201 = 793940761424319
BaseRepresentation
bin100011011001001001101111…
…1000110100011100111110001
31111211021220201201001102220202
41012302103133012203213301
5311301132133021134301
63022042300443244545
7122401065412333145
oct10662233706434761
91454256651042822
10311320152521201
1190218153aa912a
122aabbb21219755
1310493497804a15
1456c3d93779225
1525ed241a1e66b
hex11b24df1a39f1

311320152521201 has 4 divisors (see below), whose sum is σ = 315260913945600. Its totient is φ = 307379391096804.

The previous prime is 311320152521123. The next prime is 311320152521227. The reversal of 311320152521201 is 102125251023113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311320152521201 - 222 = 311320148326897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311320152521401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1970380712081 + ... + 1970380712238.

It is an arithmetic number, because the mean of its divisors is an integer number (78815228486400).

Almost surely, 2311320152521201 is an apocalyptic number.

It is an amenable number.

311320152521201 is a deficient number, since it is larger than the sum of its proper divisors (3940761424399).

311320152521201 is an equidigital number, since it uses as much as digits as its factorization.

311320152521201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3940761424398.

The product of its (nonzero) digits is 3600, while the sum is 29.

The spelling of 311320152521201 in words is "three hundred eleven trillion, three hundred twenty billion, one hundred fifty-two million, five hundred twenty-one thousand, two hundred one".

Divisors: 1 79 3940761424319 311320152521201