3113207073113 has 4 divisors (see below), whose sum is σ = 3185607237648. Its totient is φ = 3040806908580.

The previous prime is 3113207073103. The next prime is 3113207073133. The reversal of 3113207073113 is 3113707023113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3113207073113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3113207073113.

It is not an unprimeable number, because it can be changed into a prime (3113207073103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36200082203 + ... + 36200082288.

It is an arithmetic number, because the mean of its divisors is an integer number (796401809412).

Almost surely, 2^{3113207073113} is an apocalyptic number.

It is an amenable number.

3113207073113 is a deficient number, since it is larger than the sum of its proper divisors (72400164535).

3113207073113 is an equidigital number, since it uses as much as digits as its factorization.

3113207073113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72400164534.

The product of its (nonzero) digits is 7938, while the sum is 32.

The spelling of 3113207073113 in words is "three trillion, one hundred thirteen billion, two hundred seven million, seventy-three thousand, one hundred thirteen".