Base | Representation |
---|---|
bin | 101101010011011001111… |
… | …101100111100011111011 |
3 | 102000121202011202012221011 |
4 | 231103121331213203323 |
5 | 402001330030143003 |
6 | 10342105041454351 |
7 | 440631215664313 |
oct | 55233175474373 |
9 | 12017664665834 |
10 | 3113213131003 |
11 | aa0340718758 |
12 | 4234409413b7 |
13 | 197761915351 |
14 | aa974b22443 |
15 | 55ead98046d |
hex | 2d4d9f678fb |
3113213131003 has 2 divisors, whose sum is σ = 3113213131004. Its totient is φ = 3113213131002.
The previous prime is 3113213130983. The next prime is 3113213131031. The reversal of 3113213131003 is 3001313123113.
3113213131003 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (3001313123113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3113213131003 - 217 = 3113212999931 is a prime.
It is not a weakly prime, because it can be changed into another prime (3113213137003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556606565501 + 1556606565502.
It is an arithmetic number, because the mean of its divisors is an integer number (1556606565502).
Almost surely, 23113213131003 is an apocalyptic number.
3113213131003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113213131003 is an equidigital number, since it uses as much as digits as its factorization.
3113213131003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 3113213131003 its reverse (3001313123113), we get a palindrome (6114526254116).
The spelling of 3113213131003 in words is "three trillion, one hundred thirteen billion, two hundred thirteen million, one hundred thirty-one thousand, three".
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