3113232000121 has 4 divisors (see below), whose sum is σ = 3141793761700. Its totient is φ = 3084670238544.

The previous prime is 3113232000089. The next prime is 3113232000163. The reversal of 3113232000121 is 1210002323113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2531802874896 + 581429125225 = 1591164^2 + 762515^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113232000121 - 2⁵ = 3113232000089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3113232000191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14280880626 + ... + 14280880843.

It is an arithmetic number, because the mean of its divisors is an integer number (785448440425).

Almost surely, 2^{3113232000121} is an apocalyptic number.

It is an amenable number.

3113232000121 is a deficient number, since it is larger than the sum of its proper divisors (28561761579).

3113232000121 is a wasteful number, since it uses less digits than its factorization.

3113232000121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28561761578.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 3113232000121 its reverse (1210002323113), we get a palindrome (4323234323234).

The spelling of 3113232000121 in words is "three trillion, one hundred thirteen billion, two hundred thirty-two million, one hundred twenty-one", and thus it is an aban number.