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3113232433 is a prime number
BaseRepresentation
bin1011100110010000…
…0010100000110001
322000222002121000221
42321210002200301
522333441414213
61232531213041
7140102016253
oct27144024061
98028077027
103113232433
11135837a673
1272a747181
133a7cabc8c
1421767dcd3
151334ae38d
hexb9902831

3113232433 has 2 divisors, whose sum is σ = 3113232434. Its totient is φ = 3113232432.

The previous prime is 3113232427. The next prime is 3113232467. The reversal of 3113232433 is 3342323113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2274145344 + 839087089 = 47688^2 + 28967^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113232433 - 25 = 3113232401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3113232398 and 3113232407.

It is not a weakly prime, because it can be changed into another prime (3113232233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556616216 + 1556616217.

It is an arithmetic number, because the mean of its divisors is an integer number (1556616217).

Almost surely, 23113232433 is an apocalyptic number.

It is an amenable number.

3113232433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113232433 is an equidigital number, since it uses as much as digits as its factorization.

3113232433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 25.

The square root of 3113232433 is about 55796.3478464317. The cubic root of 3113232433 is about 1460.1714368337.

Adding to 3113232433 its reverse (3342323113), we get a palindrome (6455555546).

The spelling of 3113232433 in words is "three billion, one hundred thirteen million, two hundred thirty-two thousand, four hundred thirty-three".