311327141723113 has 4 divisors (see below), whose sum is σ = 311570556221440. Its totient is φ = 311083727224788.

The previous prime is 311327141723071. The next prime is 311327141723119.

311327141723113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311327141723113 - 2²¹ = 311327139625961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311327141723119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121707247245 + ... + 121707249802.

It is an arithmetic number, because the mean of its divisors is an integer number (77892639055360).

Almost surely, 2^{311327141723113} is an apocalyptic number.

It is an amenable number.

311327141723113 is a deficient number, since it is larger than the sum of its proper divisors (243414498327).

311327141723113 is a wasteful number, since it uses less digits than its factorization.

311327141723113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243414498326.

The product of its digits is 63504, while the sum is 40.

The spelling of 311327141723113 in words is "three hundred eleven trillion, three hundred twenty-seven billion, one hundred forty-one million, seven hundred twenty-three thousand, one hundred thirteen".