Base | Representation |
---|---|
bin | 11100111111101011… |
… | …000011010100110001 |
3 | 2222100201021100122222 |
4 | 130333223003110301 |
5 | 1002230023141424 |
6 | 22145144410425 |
7 | 2151335213333 |
oct | 347753032461 |
9 | 88321240588 |
10 | 31133021489 |
11 | 12226862929 |
12 | 604a476a15 |
13 | 2c2203810b |
14 | 1714b01453 |
15 | c23333e5e |
hex | 73fac3531 |
31133021489 has 2 divisors, whose sum is σ = 31133021490. Its totient is φ = 31133021488.
The previous prime is 31133021483. The next prime is 31133021503. The reversal of 31133021489 is 98412033113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29589160225 + 1543861264 = 172015^2 + 39292^2 .
It is an emirp because it is prime and its reverse (98412033113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31133021489 - 28 = 31133021233 is a prime.
It is not a weakly prime, because it can be changed into another prime (31133021483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15566510744 + 15566510745.
It is an arithmetic number, because the mean of its divisors is an integer number (15566510745).
Almost surely, 231133021489 is an apocalyptic number.
It is an amenable number.
31133021489 is a deficient number, since it is larger than the sum of its proper divisors (1).
31133021489 is an equidigital number, since it uses as much as digits as its factorization.
31133021489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 31133021489 in words is "thirty-one billion, one hundred thirty-three million, twenty-one thousand, four hundred eighty-nine".
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