Base | Representation |
---|---|
bin | 101101010011011111110… |
… | …111111011010000000001 |
3 | 102000122000002100122002001 |
4 | 231103133313323100001 |
5 | 402002030422131311 |
6 | 10342122543224001 |
7 | 440633531634652 |
oct | 55233767732001 |
9 | 12018002318061 |
10 | 3113312302081 |
11 | aa03916a3423 |
12 | 423469ba8001 |
13 | 197779328767 |
14 | aa983d79529 |
15 | 55eb751e4c1 |
hex | 2d4dfdfb401 |
3113312302081 has 2 divisors, whose sum is σ = 3113312302082. Its totient is φ = 3113312302080.
The previous prime is 3113312301889. The next prime is 3113312302117. The reversal of 3113312302081 is 1802032133113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1771004685681 + 1342307616400 = 1330791^2 + 1158580^2 .
It is a cyclic number.
It is not a de Polignac number, because 3113312302081 - 221 = 3113310204929 is a prime.
It is a super-2 number, since 2×31133123020812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3113312300081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556656151040 + 1556656151041.
It is an arithmetic number, because the mean of its divisors is an integer number (1556656151041).
Almost surely, 23113312302081 is an apocalyptic number.
It is an amenable number.
3113312302081 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113312302081 is an equidigital number, since it uses as much as digits as its factorization.
3113312302081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 3113312302081 its reverse (1802032133113), we get a palindrome (4915344435194).
The spelling of 3113312302081 in words is "three trillion, one hundred thirteen billion, three hundred twelve million, three hundred two thousand, eighty-one".
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