311334202433113 has 4 divisors (see below), whose sum is σ = 311337583762660. Its totient is φ = 311330821103568.

The previous prime is 311334202433081. The next prime is 311334202433117.

311334202433113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 181304151395929 + 130030051037184 = 13464923^2 + 11403072^2 .

It is a cyclic number.

It is not a de Polignac number, because 311334202433113 - 2⁵ = 311334202433081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311334202433117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1690526658 + ... + 1690710811.

It is an arithmetic number, because the mean of its divisors is an integer number (77834395940665).

Almost surely, 2^{311334202433113} is an apocalyptic number.

It is an amenable number.

311334202433113 is a deficient number, since it is larger than the sum of its proper divisors (3381329547).

311334202433113 is an equidigital number, since it uses as much as digits as its factorization.

311334202433113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3381329546.

The product of its (nonzero) digits is 46656, while the sum is 34.

It can be divided in two parts, 31133420 and 2433113, that added together give a palindrome (33566533).

The spelling of 311334202433113 in words is "three hundred eleven trillion, three hundred thirty-four billion, two hundred two million, four hundred thirty-three thousand, one hundred thirteen".