3113402043113 has 4 divisors (see below), whose sum is σ = 3277265308560. Its totient is φ = 2949538777668.

The previous prime is 3113402043091. The next prime is 3113402043233.

3113402043113 is nontrivially palindromic in base 10.

3113402043113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3113402043113 - 2¹⁰ = 3113402042089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3113402049113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81931632695 + ... + 81931632732.

It is an arithmetic number, because the mean of its divisors is an integer number (819316327140).

Almost surely, 2^{3113402043113} is an apocalyptic number.

It is an amenable number.

3113402043113 is a deficient number, since it is larger than the sum of its proper divisors (163863265447).

3113402043113 is a wasteful number, since it uses less digits than its factorization.

3113402043113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163863265446.

The product of its (nonzero) digits is 2592, while the sum is 26.

The spelling of 3113402043113 in words is "three trillion, one hundred thirteen billion, four hundred two million, forty-three thousand, one hundred thirteen".