Base | Representation |
---|---|
bin | 100011011001010100100101… |
… | …0100111011010011101101010 |
3 | 1111211101010211000212110002101 |
4 | 1012302221022213122131222 |
5 | 311302022321332224114 |
6 | 3022101110412524014 |
7 | 122402551315302136 |
oct | 10662511247323552 |
9 | 1454333730773071 |
10 | 311343431133034 |
11 | 9022700a193803 |
12 | 2ab0453918060a |
13 | 10495737513751 |
14 | 56c51612703c6 |
15 | 25edb55515d74 |
hex | 11b2a4a9da76a |
311343431133034 has 4 divisors (see below), whose sum is σ = 467015146699554. Its totient is φ = 155671715566516.
The previous prime is 311343431132911. The next prime is 311343431133073. The reversal of 311343431133034 is 430331134343113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 296762465972025 + 14580965161009 = 17226795^2 + 3818503^2 .
It is a junction number, because it is equal to n+sod(n) for n = 311343431132984 and 311343431133002.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77835857783257 + ... + 77835857783260.
Almost surely, 2311343431133034 is an apocalyptic number.
311343431133034 is a deficient number, since it is larger than the sum of its proper divisors (155671715566520).
311343431133034 is a wasteful number, since it uses less digits than its factorization.
311343431133034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 155671715566519.
The product of its (nonzero) digits is 139968, while the sum is 37.
Adding to 311343431133034 its reverse (430331134343113), we get a palindrome (741674565476147).
The spelling of 311343431133034 in words is "three hundred eleven trillion, three hundred forty-three billion, four hundred thirty-one million, one hundred thirty-three thousand, thirty-four".
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