Base | Representation |
---|---|
bin | 1110001010001000010101… |
… | …11110101001000110000010 |
3 | 11002020102100000102101212202 |
4 | 13011010022332221012002 |
5 | 13040101223420401424 |
6 | 150114540305353202 |
7 | 6362246336336654 |
oct | 705041276510602 |
9 | 132212300371782 |
10 | 31134402122114 |
11 | 9a14031364625 |
12 | 35aa080338802 |
13 | 144ac666064a5 |
14 | 798cad7aa6d4 |
15 | 38ed25aab2ae |
hex | 1c510afa9182 |
31134402122114 has 4 divisors (see below), whose sum is σ = 46701603183174. Its totient is φ = 15567201061056.
The previous prime is 31134402122113. The next prime is 31134402122143. The reversal of 31134402122114 is 41122120443113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 15578280106489 + 15556122015625 = 3946933^2 + 3944125^2 .
It is not an unprimeable number, because it can be changed into a prime (31134402122113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7783600530527 + ... + 7783600530530.
Almost surely, 231134402122114 is an apocalyptic number.
31134402122114 is a deficient number, since it is larger than the sum of its proper divisors (15567201061060).
31134402122114 is a wasteful number, since it uses less digits than its factorization.
31134402122114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15567201061059.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 31134402122114 its reverse (41122120443113), we get a palindrome (72256522565227).
The spelling of 31134402122114 in words is "thirty-one trillion, one hundred thirty-four billion, four hundred two million, one hundred twenty-two thousand, one hundred fourteen".
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