Base | Representation |
---|---|
bin | 100011011001110001010000… |
… | …0101101111000100101101011 |
3 | 1111211121000202020100202020222 |
4 | 1012303202200231320211223 |
5 | 311304024422313241021 |
6 | 3022145252351040255 |
7 | 122410161220320314 |
oct | 10663424055704553 |
9 | 1454530666322228 |
10 | 311405005212011 |
11 | 90250137148687 |
12 | 2ab1446221008b |
13 | 1049b49b0cc1c9 |
14 | 56c8122bcb60b |
15 | 260055b0476ab |
hex | 11b38a0b7896b |
311405005212011 has 4 divisors (see below), whose sum is σ = 312776833429032. Its totient is φ = 310033176994992.
The previous prime is 311405005211987. The next prime is 311405005212019. The reversal of 311405005212011 is 110212500504113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 311405005212011 - 234 = 311387825342827 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (311405005212019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 685914108170 + ... + 685914108623.
It is an arithmetic number, because the mean of its divisors is an integer number (78194208357258).
Almost surely, 2311405005212011 is an apocalyptic number.
311405005212011 is a deficient number, since it is larger than the sum of its proper divisors (1371828217021).
311405005212011 is a wasteful number, since it uses less digits than its factorization.
311405005212011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1371828217020.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 311405005212011 its reverse (110212500504113), we get a palindrome (421617505716124).
The spelling of 311405005212011 in words is "three hundred eleven trillion, four hundred five billion, five million, two hundred twelve thousand, eleven".
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