Base | Representation |
---|---|
bin | 101101010100001101011… |
… | …011010100010010110011 |
3 | 102000200222100102200012012 |
4 | 231110031123110102303 |
5 | 402010112044220134 |
6 | 10342330443553135 |
7 | 440661501653615 |
oct | 55241533242263 |
9 | 12020870380165 |
10 | 3114076554419 |
11 | aa0744038526 |
12 | 423641b2b7ab |
13 | 19786b77348c |
14 | aaa1767adb5 |
15 | 5600e6846ce |
hex | 2d50d6d44b3 |
3114076554419 has 2 divisors, whose sum is σ = 3114076554420. Its totient is φ = 3114076554418.
The previous prime is 3114076554349. The next prime is 3114076554487. The reversal of 3114076554419 is 9144556704113.
3114076554419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3114076554419 - 240 = 2014564926643 is a prime.
It is a super-2 number, since 2×31140765544192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3114006554419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557038277209 + 1557038277210.
It is an arithmetic number, because the mean of its divisors is an integer number (1557038277210).
Almost surely, 23114076554419 is an apocalyptic number.
3114076554419 is a deficient number, since it is larger than the sum of its proper divisors (1).
3114076554419 is an equidigital number, since it uses as much as digits as its factorization.
3114076554419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1814400, while the sum is 50.
The spelling of 3114076554419 in words is "three trillion, one hundred fourteen billion, seventy-six million, five hundred fifty-four thousand, four hundred nineteen".
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