Base | Representation |
---|---|
bin | 101101010100001111100… |
… | …010100111111101101011 |
3 | 102000201001211011201220012 |
4 | 231110033202213331223 |
5 | 402010200134240202 |
6 | 10342334152122135 |
7 | 440662412313665 |
oct | 55241742477553 |
9 | 12021054151805 |
10 | 3114112024427 |
11 | aa0762064688 |
12 | 42365199634b |
13 | 197875c12151 |
14 | aaa1c271535 |
15 | 5601283e152 |
hex | 2d50f8a7f6b |
3114112024427 has 2 divisors, whose sum is σ = 3114112024428. Its totient is φ = 3114112024426.
The previous prime is 3114112024393. The next prime is 3114112024477. The reversal of 3114112024427 is 7244202114113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3114112024427 - 210 = 3114112023403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3114112024393 and 3114112024402.
It is not a weakly prime, because it can be changed into another prime (3114112024477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557056012213 + 1557056012214.
It is an arithmetic number, because the mean of its divisors is an integer number (1557056012214).
Almost surely, 23114112024427 is an apocalyptic number.
3114112024427 is a deficient number, since it is larger than the sum of its proper divisors (1).
3114112024427 is an equidigital number, since it uses as much as digits as its factorization.
3114112024427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 32.
The spelling of 3114112024427 in words is "three trillion, one hundred fourteen billion, one hundred twelve million, twenty-four thousand, four hundred twenty-seven".
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