Base | Representation |
---|---|
bin | 1110001010010101000011… |
… | …00110000111100011101011 |
3 | 11002021001221110000201202221 |
4 | 13011022201212013203223 |
5 | 13040204211322121303 |
6 | 150122025242334511 |
7 | 6362610363454453 |
oct | 705124146074353 |
9 | 132231843021687 |
10 | 31141224020203 |
11 | 9a16a12122630 |
12 | 35ab464aba437 |
13 | 144b7b2a5148b |
14 | 799359804d63 |
15 | 3900c49444bd |
hex | 1c52a19878eb |
31141224020203 has 32 divisors (see below), whose sum is σ = 35798289120000. Its totient is φ = 26791684053120.
The previous prime is 31141224020167. The next prime is 31141224020339. The reversal of 31141224020203 is 30202042214113.
It is a cyclic number.
It is not a de Polignac number, because 31141224020203 - 229 = 31140687149291 is a prime.
It is a super-2 number, since 2×311412240202032 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31141224026203) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 827786928 + ... + 827824546.
It is an arithmetic number, because the mean of its divisors is an integer number (1118696535000).
Almost surely, 231141224020203 is an apocalyptic number.
31141224020203 is a deficient number, since it is larger than the sum of its proper divisors (4657065099797).
31141224020203 is a wasteful number, since it uses less digits than its factorization.
31141224020203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41755.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 31141224020203 its reverse (30202042214113), we get a palindrome (61343266234316).
The spelling of 31141224020203 in words is "thirty-one trillion, one hundred forty-one billion, two hundred twenty-four million, twenty thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •